25x^2=40x=-16

Solution for 25x^2=40x=-16 equation:

25x^2=40x=-16

We move all terms to the left:

25x^2-(40x)=0

a = 25; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·25·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*25}=\frac{0}{50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*25}=\frac{80}{50}
=1+3/5
$